(4x^2)+4x+11=0

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Solution for (4x^2)+4x+11=0 equation:


Simplifying
(4x2) + 4x + 11 = 0

Reorder the terms:
11 + 4x + (4x2) = 0

Solving
11 + 4x + (4x2) = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
2.75 + x + x2 = 0

Move the constant term to the right:

Add '-2.75' to each side of the equation.
2.75 + x + -2.75 + x2 = 0 + -2.75

Reorder the terms:
2.75 + -2.75 + x + x2 = 0 + -2.75

Combine like terms: 2.75 + -2.75 = 0.00
0.00 + x + x2 = 0 + -2.75
x + x2 = 0 + -2.75

Combine like terms: 0 + -2.75 = -2.75
x + x2 = -2.75

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
 + 0.25 + x2 = -2.75 + 0.25

Combine like terms:  + 0.25 = 1.25
1.25 + x2 = -2.75 + 0.25

Combine like terms: -2.75 + 0.25 = -2.5
1.25 + x2 = -2.5

Factor a perfect square on the left side:
((x) + 0.5)((x) + 0.5) = -2.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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